# Determine the volume of NO2 obtained if 7.5 liters of oxygen were formed in the reaction

September 20, 2021 | education

| Let’s write down the solution according to the condition of the problem:

X l -? V = 7.5 liters.

1.2AgNO3 = 2Ag + 2NO2 + O2 – OBP, silver is obtained, nitric oxide is released (4);

2. Calculations:

M (NO2) = 46 g / mol;

M (O2) = 36 g / mol.

3. We make up the proportions:

1 mol of gas at normal level – 22.4 liters;

X mol (O2) – 7.5 liters. hence, X mol (O2) = 1 * 7.5 / 22.4 = 0.33 mol;

X mol (NO2) – 0.33 mol (О2);

-2 mol -1 mol hence, X mol (NO2) = 2 * 0.33 / 1 = 0.66 mol.

3. Let’s calculate the volume of the product:

V (NO2) = 0.66 * 22.4 = 14.78 liters.

Answer: during the reaction, nitrogen oxide with a volume of 14.78 liters was obtained.

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